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URL title: What's the sign of C's remainder operator "%"? - Tom Mewett
URL paragraphs: TL;DR In C99 or later, the sign of a%b is the same as a ; earlier than C99 it is implementation-defined. The standard says the sign of a%b is such that (a/b)*b + a%b == a . In other words, a%b == a - (a/b)*b . Assuming C99, a/b always rounds towards zero;
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