URL details: www.pandaomeng.com/

URL title: Hexo
URL paragraphs: Patrick Pan nums = [1, 2, 4, 3] 原地前缀和, 新的 nums[i] 表示 0 ~ i 的累计和 1 2 3 n = len(nums) for i in range(1, n): nums[i] += nums[i - 1] 另外一种写法, 得到的 s 的长度为 n + 1, s[0] = 0 1 s = list(accumulate(nums, initial=0))
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2022-08-12
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